In a circuit with a 9V battery and three resistors (3Ω, 3Ω, and 3Ω) in series, w

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Question: In a circuit with a 9V battery and three resistors (3Ω, 3Ω, and 3Ω) in series, what is the voltage across each resistor?

Options:

Correct Answer: 3V

Solution:

In a series circuit, the voltage is divided equally among the resistors. Therefore, V across each 3Ω resistor = 9V / 3 = 3V.

In a circuit with a 9V battery and three resistors (3Ω, 3Ω, and 3Ω) in series, what is the voltage across each resistor?

In a circuit with a 9V battery and three resistors (3Ω, 3Ω, and 3Ω) in series, what is the voltage across each resistor?

Correct Answer: 3V

Step 1: Identify the total voltage in the circuit, which is given as 9V from the battery.
Step 2: Identify the number of resistors in the circuit, which are three 3Ω resistors.
Step 3: Understand that in a series circuit, the total voltage is divided equally among all the resistors.
Step 4: Calculate the total resistance by adding the resistance of each resistor: 3Ω + 3Ω + 3Ω = 9Ω.
Step 5: Since there are three resistors, divide the total voltage by the number of resistors: 9V / 3 = 3V.
Step 6: Conclude that the voltage across each 3Ω resistor is 3V.

Voltage Division in Series Circuits – In a series circuit, the total voltage is divided among the resistors based on their resistance values, and in this case, equal resistors share the voltage equally.