In a circuit with a 10V battery and two resistors of 5Ω each in series, what is

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Question: In a circuit with a 10V battery and two resistors of 5Ω each in series, what is the voltage across the second resistor?

Options:

Correct Answer: 5V

Solution:

In series, the voltage is divided equally: V2 = (R2 / (R1 + R2)) * Vtotal = (5 / (5 + 5)) * 10 = 5V.

In a circuit with a 10V battery and two resistors of 5Ω each in series, what is the voltage across the second resistor?

In a circuit with a 10V battery and two resistors of 5Ω each in series, what is the voltage across the second resistor?

Correct Answer: 5V

Step 1: Identify the total voltage in the circuit, which is given as 10V from the battery.
Step 2: Identify the resistors in the circuit. There are two resistors, R1 and R2, each with a resistance of 5Ω.
Step 3: Since the resistors are in series, the total resistance (Rtotal) is the sum of the individual resistances: Rtotal = R1 + R2 = 5Ω + 5Ω = 10Ω.
Step 4: Calculate the voltage across the second resistor (R2) using the formula: V2 = (R2 / Rtotal) * Vtotal.
Step 5: Substitute the values into the formula: V2 = (5Ω / 10Ω) * 10V.
Step 6: Simplify the calculation: V2 = (1/2) * 10V = 5V.
Step 7: Conclude that the voltage across the second resistor is 5V.

Voltage Division in Series Circuits – In a series circuit, the total voltage is divided among the resistors based on their resistance values.