If a circuit has a total voltage of 24V and two resistors of 8Ω and 4Ω in series

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Question: If a circuit has a total voltage of 24V and two resistors of 8Ω and 4Ω in series, what is the current flowing through the circuit?

Options:

Correct Answer: 2A

Solution:

Total resistance R_total = 8Ω + 4Ω = 12Ω. Using Ohm\'s law, I = V/R = 24V/12Ω = 2A.

If a circuit has a total voltage of 24V and two resistors of 8Ω and 4Ω in series, what is the current flowing through the circuit?

If a circuit has a total voltage of 24V and two resistors of 8Ω and 4Ω in series, what is the current flowing through the circuit?

Correct Answer: 2A

Step 1: Identify the total voltage in the circuit, which is given as 24V.
Step 2: Identify the two resistors in the circuit, which are 8Ω and 4Ω.
Step 3: Calculate the total resistance by adding the two resistors together: 8Ω + 4Ω = 12Ω.
Step 4: Use Ohm's law to find the current. Ohm's law states that current (I) equals voltage (V) divided by resistance (R).
Step 5: Substitute the values into the formula: I = 24V / 12Ω.
Step 6: Calculate the current: I = 2A.

Ohm's Law – Ohm's Law states that the current (I) through a conductor between two points is directly proportional to the voltage (V) across the two points and inversely proportional to the resistance (R) of the conductor.
Series Circuits – In a series circuit, the total resistance is the sum of the individual resistances, and the same current flows through all components.