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If a circuit has a total voltage of 24V and two resistors of 8Ω and 4Ω in series
If a circuit has a total voltage of 24V and two resistors of 8Ω and 4Ω in series, what is the current flowing through the circuit?
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If a circuit has a total voltage of 24V and two resistors of 8Ω and 4Ω in series, what is the current flowing through the circuit?
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Total resistance R_total = 8Ω + 4Ω = 12Ω. Using Ohm's law, I = V/R = 24V/12Ω = 2A.
Questions & Step-by-step Solutions
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Q
Q: If a circuit has a total voltage of 24V and two resistors of 8Ω and 4Ω in series, what is the current flowing through the circuit?
Solution:
Total resistance R_total = 8Ω + 4Ω = 12Ω. Using Ohm's law, I = V/R = 24V/12Ω = 2A.
Steps: 6
Show Steps
Step 1: Identify the total voltage in the circuit, which is given as 24V.
Step 2: Identify the two resistors in the circuit, which are 8Ω and 4Ω.
Step 3: Calculate the total resistance by adding the two resistors together: 8Ω + 4Ω = 12Ω.
Step 4: Use Ohm's law to find the current. Ohm's law states that current (I) equals voltage (V) divided by resistance (R).
Step 5: Substitute the values into the formula: I = 24V / 12Ω.
Step 6: Calculate the current: I = 2A.
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