What is the total resistance in a circuit with a 12Ω resistor and a 4Ω resistor

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Question: What is the total resistance in a circuit with a 12Ω resistor and a 4Ω resistor connected in series?

Options:

Correct Answer: 16Ω

Solution:

In series, total resistance R_total = R1 + R2 = 12Ω + 4Ω = 16Ω.

What is the total resistance in a circuit with a 12Ω resistor and a 4Ω resistor connected in series?

What is the total resistance in a circuit with a 12Ω resistor and a 4Ω resistor connected in series?

Correct Answer: 16Ω

Step 1: Identify the resistors in the circuit. We have a 12Ω resistor and a 4Ω resistor.
Step 2: Understand that when resistors are connected in series, the total resistance is the sum of the individual resistances.
Step 3: Write down the formula for total resistance in series: R_total = R1 + R2.
Step 4: Substitute the values of the resistors into the formula: R_total = 12Ω + 4Ω.
Step 5: Perform the addition: 12Ω + 4Ω = 16Ω.
Step 6: Conclude that the total resistance in the circuit is 16Ω.

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