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In a circuit with two resistors in parallel, if one resistor is 6Ω and the other

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Question: In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current flowing through the circuit when connected to a 12V battery?

Options:

  1. 2A
  2. 4A
  3. 6A
  4. 8A

Correct Answer: 4A

Solution: 

First, find the equivalent resistance: 1/R_eq = 1/6 + 1/3 = 1/2, R_eq = 2Ω. Then, I = V/R = 12V/2Ω = 6A.

In a circuit with two resistors in parallel, if one resistor is 6Ω and the other

Practice Questions

Q1
In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current flowing through the circuit when connected to a 12V battery?
  1. 2A
  2. 4A
  3. 6A
  4. 8A

Questions & Step-by-Step Solutions

In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current flowing through the circuit when connected to a 12V battery?
  • Step 1: Identify the resistors in the circuit. We have one resistor of 6Ω and another of 3Ω.
  • Step 2: Use the formula for equivalent resistance in parallel: 1/R_eq = 1/R1 + 1/R2.
  • Step 3: Substitute the values into the formula: 1/R_eq = 1/6 + 1/3.
  • Step 4: Find a common denominator to add the fractions. The common denominator for 6 and 3 is 6.
  • Step 5: Rewrite 1/3 as 2/6, so now we have: 1/R_eq = 1/6 + 2/6 = 3/6.
  • Step 6: Simplify 3/6 to 1/2, so 1/R_eq = 1/2.
  • Step 7: To find R_eq, take the reciprocal: R_eq = 2Ω.
  • Step 8: Now, use Ohm's Law to find the total current: I = V/R.
  • Step 9: Substitute the values: I = 12V / 2Ω.
  • Step 10: Calculate the current: I = 6A.
  • Parallel Resistors – Understanding how to calculate equivalent resistance for resistors in parallel.
  • Ohm's Law – Applying Ohm's Law (V = IR) to find current in a circuit.
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