In a circuit with two resistors in parallel, if one resistor is 6Ω and the other
Practice Questions
Q1
In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current flowing through the circuit when connected to a 12V battery?
2A
4A
6A
8A
Questions & Step-by-Step Solutions
In a circuit with two resistors in parallel, if one resistor is 6Ω and the other is 3Ω, what is the total current flowing through the circuit when connected to a 12V battery?
Step 1: Identify the resistors in the circuit. We have one resistor of 6Ω and another of 3Ω.
Step 2: Use the formula for equivalent resistance in parallel: 1/R_eq = 1/R1 + 1/R2.
Step 3: Substitute the values into the formula: 1/R_eq = 1/6 + 1/3.
Step 4: Find a common denominator to add the fractions. The common denominator for 6 and 3 is 6.
Step 5: Rewrite 1/3 as 2/6, so now we have: 1/R_eq = 1/6 + 2/6 = 3/6.
Step 6: Simplify 3/6 to 1/2, so 1/R_eq = 1/2.
Step 7: To find R_eq, take the reciprocal: R_eq = 2Ω.
Step 8: Now, use Ohm's Law to find the total current: I = V/R.
