In a closed loop circuit, if the sum of the voltage rises is 20V and the sum of the voltage drops is 15V, what is the net voltage in the loop according to Kirchhoff's Voltage Law?
Practice Questions
1 question
Q1
In a closed loop circuit, if the sum of the voltage rises is 20V and the sum of the voltage drops is 15V, what is the net voltage in the loop according to Kirchhoff's Voltage Law?
5V
15V
20V
35V
According to Kirchhoff's Voltage Law, the net voltage in the loop is the sum of voltage rises minus the sum of voltage drops: 20V - 15V = 5V.
Questions & Step-by-step Solutions
1 item
Q
Q: In a closed loop circuit, if the sum of the voltage rises is 20V and the sum of the voltage drops is 15V, what is the net voltage in the loop according to Kirchhoff's Voltage Law?
Solution: According to Kirchhoff's Voltage Law, the net voltage in the loop is the sum of voltage rises minus the sum of voltage drops: 20V - 15V = 5V.
Steps: 5
Step 1: Identify the total voltage rises in the circuit. In this case, it is 20V.
Step 2: Identify the total voltage drops in the circuit. In this case, it is 15V.
Step 3: Use Kirchhoff's Voltage Law, which states that the net voltage in a closed loop is the sum of voltage rises minus the sum of voltage drops.
Step 4: Calculate the net voltage by subtracting the total voltage drops from the total voltage rises: 20V - 15V.
Step 5: Write down the result of the calculation, which is 5V.
