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What is the equivalent resistance of three resistors of values 2Ω, 3Ω, and 5Ω co
What is the equivalent resistance of three resistors of values 2Ω, 3Ω, and 5Ω connected in parallel?
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Practice Questions
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Q1
What is the equivalent resistance of three resistors of values 2Ω, 3Ω, and 5Ω connected in parallel?
1Ω
2Ω
0.83Ω
10Ω
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1/R_eq = 1/R1 + 1/R2 + 1/R3 = 1/2 + 1/3 + 1/5 = 0.8333, thus R_eq = 1.2Ω.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the equivalent resistance of three resistors of values 2Ω, 3Ω, and 5Ω connected in parallel?
Solution:
1/R_eq = 1/R1 + 1/R2 + 1/R3 = 1/2 + 1/3 + 1/5 = 0.8333, thus R_eq = 1.2Ω.
Steps: 7
Show Steps
Step 1: Identify the values of the resistors. We have R1 = 2Ω, R2 = 3Ω, and R3 = 5Ω.
Step 2: Write the formula for equivalent resistance in parallel: 1/R_eq = 1/R1 + 1/R2 + 1/R3.
Step 3: Substitute the values into the formula: 1/R_eq = 1/2 + 1/3 + 1/5.
Step 4: Calculate each term: 1/2 = 0.5, 1/3 ≈ 0.3333, and 1/5 = 0.2.
Step 5: Add the values together: 0.5 + 0.3333 + 0.2 = 1.0333.
Step 6: Take the reciprocal to find R_eq: R_eq = 1 / 1.0333 ≈ 0.967Ω.
Step 7: Round the answer to two decimal places if needed: R_eq ≈ 0.97Ω.
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