According to Kirchhoff's Current Law, if three currents entering a junction are 2A, 3A, and 5A, what is the total current leaving the junction?
Practice Questions
1 question
Q1
According to Kirchhoff's Current Law, if three currents entering a junction are 2A, 3A, and 5A, what is the total current leaving the junction?
10A
5A
3A
2A
According to Kirchhoff's Current Law, the total current entering a junction equals the total current leaving it. Therefore, total current leaving = 2A + 3A + 5A = 10A.
Questions & Step-by-step Solutions
1 item
Q
Q: According to Kirchhoff's Current Law, if three currents entering a junction are 2A, 3A, and 5A, what is the total current leaving the junction?
Solution: According to Kirchhoff's Current Law, the total current entering a junction equals the total current leaving it. Therefore, total current leaving = 2A + 3A + 5A = 10A.
Steps: 5
Step 1: Identify the currents entering the junction. In this case, they are 2A, 3A, and 5A.
Step 2: Add the currents that are entering the junction together. So, calculate 2A + 3A + 5A.
Step 3: Perform the addition: 2A + 3A = 5A, then 5A + 5A = 10A.
Step 4: According to Kirchhoff's Current Law, the total current entering the junction (10A) must equal the total current leaving the junction.
Step 5: Therefore, the total current leaving the junction is 10A.
