In a circuit with a 12V battery and two resistors of 4Ω and 8Ω in series, what i

₹0.0

Question: In a circuit with a 12V battery and two resistors of 4Ω and 8Ω in series, what is the current flowing through the circuit?

Options:

Correct Answer: 1A

Solution:

Total resistance R = R1 + R2 = 4Ω + 8Ω = 12Ω. Current I = V/R = 12V / 12Ω = 1A.

In a circuit with a 12V battery and two resistors of 4Ω and 8Ω in series, what is the current flowing through the circuit?

In a circuit with a 12V battery and two resistors of 4Ω and 8Ω in series, what is the current flowing through the circuit?

Correct Answer: 1A

Step 1: Identify the voltage of the battery, which is 12V.
Step 2: Identify the values of the resistors in the circuit, which are 4Ω and 8Ω.
Step 3: Calculate the total resistance in the circuit by adding the two resistors together: 4Ω + 8Ω = 12Ω.
Step 4: Use Ohm's Law to find the current. Ohm's Law states that Current (I) = Voltage (V) / Resistance (R).
Step 5: Substitute the values into the formula: I = 12V / 12Ω.
Step 6: Calculate the current: I = 1A.

Ohm's Law – The relationship between voltage (V), current (I), and resistance (R) in an electrical circuit, expressed as V = I * R.
Series Circuits – In a series circuit, the total resistance is the sum of individual resistances, and the same current flows through all components.