In a circuit with a 12V battery and two resistors of 4Ω and 8Ω in series, what i

In a circuit with a 12V battery and two resistors of 4Ω and 8Ω in series, what is the current flowing through the circuit?

In a circuit with a 12V battery and two resistors of 4Ω and 8Ω in series, what is the current flowing through the circuit?

Correct Answer: 1A

Step 1: Identify the voltage of the battery, which is 12V.
Step 2: Identify the values of the resistors in the circuit, which are 4Ω and 8Ω.
Step 3: Calculate the total resistance in the circuit by adding the two resistors together: 4Ω + 8Ω = 12Ω.
Step 4: Use Ohm's Law to find the current. Ohm's Law states that Current (I) = Voltage (V) / Resistance (R).
Step 5: Substitute the values into the formula: I = 12V / 12Ω.
Step 6: Calculate the current: I = 1A.

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