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If a circuit has a current of 3A flowing through a 5Ω resistor, what is the powe
If a circuit has a current of 3A flowing through a 5Ω resistor, what is the power dissipated in the resistor?
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Practice Questions
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Q1
If a circuit has a current of 3A flowing through a 5Ω resistor, what is the power dissipated in the resistor?
15W
9W
5W
3W
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Power (P) = I^2 * R = (3A)^2 * 5Ω = 9A^2 * 5Ω = 45W.
Questions & Step-by-step Solutions
1 item
Q
Q: If a circuit has a current of 3A flowing through a 5Ω resistor, what is the power dissipated in the resistor?
Solution:
Power (P) = I^2 * R = (3A)^2 * 5Ω = 9A^2 * 5Ω = 45W.
Steps: 7
Show Steps
Step 1: Identify the current (I) flowing through the resistor. In this case, I = 3A.
Step 2: Identify the resistance (R) of the resistor. Here, R = 5Ω.
Step 3: Use the formula for power (P) dissipated in a resistor, which is P = I^2 * R.
Step 4: Substitute the values into the formula: P = (3A)^2 * 5Ω.
Step 5: Calculate (3A)^2, which equals 9A^2.
Step 6: Multiply 9A^2 by 5Ω to find the power: 9A^2 * 5Ω = 45W.
Step 7: Conclude that the power dissipated in the resistor is 45W.
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