In a circuit with a 12V battery and two resistors of 4Ω and 8Ω in series, what i

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Question: In a circuit with a 12V battery and two resistors of 4Ω and 8Ω in series, what is the voltage across the 8Ω resistor?

Options:

Correct Answer: 8V

Solution:

Using the voltage divider rule, V = (R2 / (R1 + R2)) * Vtotal = (8 / (4 + 8)) * 12 = 8V.

In a circuit with a 12V battery and two resistors of 4Ω and 8Ω in series, what is the voltage across the 8Ω resistor?

In a circuit with a 12V battery and two resistors of 4Ω and 8Ω in series, what is the voltage across the 8Ω resistor?

Correct Answer: 8V

Step 1: Identify the total voltage in the circuit, which is given as 12V from the battery.
Step 2: Identify the resistors in the circuit. We have R1 = 4Ω and R2 = 8Ω.
Step 3: Calculate the total resistance in the series circuit by adding the two resistors: Total Resistance = R1 + R2 = 4Ω + 8Ω = 12Ω.
Step 4: Use the voltage divider rule to find the voltage across the 8Ω resistor. The formula is V = (R2 / (R1 + R2)) * Vtotal.
Step 5: Substitute the values into the formula: V = (8 / (4 + 8)) * 12.
Step 6: Simplify the equation: V = (8 / 12) * 12.
Step 7: Calculate the voltage: V = 8V.

Voltage Divider Rule – The voltage divider rule is used to determine the voltage drop across a resistor in a series circuit based on its resistance relative to the total resistance.
Series Circuit – In a series circuit, the total voltage is divided among the resistors, and the same current flows through each component.
Ohm's Law – Ohm's Law relates voltage, current, and resistance in an electrical circuit, stating that V = I * R.