In a circuit with a 12V battery and two resistors of 4Ω and 8Ω in series, what is the voltage across the 8Ω resistor?

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Q: In a circuit with a 12V battery and two resistors of 4Ω and 8Ω in series, what is the voltage across the 8Ω resistor?

Solution: Using the voltage divider rule, V = (R2 / (R1 + R2)) * Vtotal = (8 / (4 + 8)) * 12 = 8V.

Steps: 7

Step 1: Identify the total voltage in the circuit, which is given as 12V from the battery.
Step 2: Identify the resistors in the circuit. We have R1 = 4Ω and R2 = 8Ω.
Step 3: Calculate the total resistance in the series circuit by adding the two resistors: Total Resistance = R1 + R2 = 4Ω + 8Ω = 12Ω.
Step 4: Use the voltage divider rule to find the voltage across the 8Ω resistor. The formula is V = (R2 / (R1 + R2)) * Vtotal.
Step 5: Substitute the values into the formula: V = (8 / (4 + 8)) * 12.
Step 6: Simplify the equation: V = (8 / 12) * 12.
Step 7: Calculate the voltage: V = 8V.