If a circuit has a total voltage of 24V and two resistors of 6Ω and 3Ω in series

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Question: If a circuit has a total voltage of 24V and two resistors of 6Ω and 3Ω in series, what is the current flowing through the circuit?

Options:

Correct Answer: 3A

Solution:

Total resistance R_total = 6Ω + 3Ω = 9Ω. Current I = V/R = 24V / 9Ω = 2.67A.

If a circuit has a total voltage of 24V and two resistors of 6Ω and 3Ω in series, what is the current flowing through the circuit?

If a circuit has a total voltage of 24V and two resistors of 6Ω and 3Ω in series, what is the current flowing through the circuit?

Correct Answer: 2.67A

Step 1: Identify the total voltage in the circuit, which is given as 24V.
Step 2: Identify the resistors in the circuit, which are 6Ω and 3Ω.
Step 3: Calculate the total resistance by adding the resistances of the two resistors: 6Ω + 3Ω = 9Ω.
Step 4: Use Ohm's Law to find the current. Ohm's Law states that Current (I) = Voltage (V) / Resistance (R).
Step 5: Substitute the values into the formula: I = 24V / 9Ω.
Step 6: Calculate the current: 24V / 9Ω = 2.67A.

Ohm's Law – The relationship between voltage (V), current (I), and resistance (R) in an electrical circuit, expressed as V = I * R.
Series Circuits – In a series circuit, the total resistance is the sum of individual resistances, and the same current flows through all components.