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If a circuit has a total voltage of 24V and two resistors of 6Ω and 3Ω in series
If a circuit has a total voltage of 24V and two resistors of 6Ω and 3Ω in series, what is the current flowing through the circuit?
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If a circuit has a total voltage of 24V and two resistors of 6Ω and 3Ω in series, what is the current flowing through the circuit?
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Total resistance R_total = 6Ω + 3Ω = 9Ω. Current I = V/R = 24V / 9Ω = 2.67A.
Questions & Step-by-step Solutions
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Q
Q: If a circuit has a total voltage of 24V and two resistors of 6Ω and 3Ω in series, what is the current flowing through the circuit?
Solution:
Total resistance R_total = 6Ω + 3Ω = 9Ω. Current I = V/R = 24V / 9Ω = 2.67A.
Steps: 6
Show Steps
Step 1: Identify the total voltage in the circuit, which is given as 24V.
Step 2: Identify the resistors in the circuit, which are 6Ω and 3Ω.
Step 3: Calculate the total resistance by adding the resistances of the two resistors: 6Ω + 3Ω = 9Ω.
Step 4: Use Ohm's Law to find the current. Ohm's Law states that Current (I) = Voltage (V) / Resistance (R).
Step 5: Substitute the values into the formula: I = 24V / 9Ω.
Step 6: Calculate the current: 24V / 9Ω = 2.67A.
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