What is the total resistance in a circuit with a 10Ω resistor in series with a 5

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Question: What is the total resistance in a circuit with a 10Ω resistor in series with a 5Ω resistor?

Options:

Correct Answer: 15Ω

Solution:

In series, total resistance (R_total) = R1 + R2 = 10Ω + 5Ω = 15Ω.

What is the total resistance in a circuit with a 10Ω resistor in series with a 5Ω resistor?

What is the total resistance in a circuit with a 10Ω resistor in series with a 5Ω resistor?

Correct Answer: 15Ω

Step 1: Identify the resistors in the circuit. We have a 10Ω resistor and a 5Ω resistor.
Step 2: Understand that in a series circuit, the total resistance is found by adding the resistances together.
Step 3: Write down the formula for total resistance in series: R_total = R1 + R2.
Step 4: Substitute the values of the resistors into the formula: R_total = 10Ω + 5Ω.
Step 5: Perform the addition: 10Ω + 5Ω = 15Ω.
Step 6: Conclude that the total resistance in the circuit is 15Ω.

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