If a circuit has a current of 3A flowing through a 5Ω resistor, what is the powe

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Question: If a circuit has a current of 3A flowing through a 5Ω resistor, what is the power dissipated by the resistor?

Options:

Correct Answer: 15W

Solution:

Power (P) = I^2 * R = (3A)^2 * 5Ω = 9 * 5 = 45W.

If a circuit has a current of 3A flowing through a 5Ω resistor, what is the power dissipated by the resistor?

If a circuit has a current of 3A flowing through a 5Ω resistor, what is the power dissipated by the resistor?

Correct Answer: 45W

Step 1: Identify the current (I) flowing through the resistor. In this case, I = 3A.
Step 2: Identify the resistance (R) of the resistor. Here, R = 5Ω.
Step 3: Use the formula for power (P) dissipated by a resistor, which is P = I^2 * R.
Step 4: Substitute the values into the formula: P = (3A)^2 * 5Ω.
Step 5: Calculate (3A)^2, which is 9.
Step 6: Multiply 9 by 5Ω to find the power: 9 * 5 = 45W.
Step 7: Conclude that the power dissipated by the resistor is 45W.

Ohm's Law and Power Calculation – Understanding the relationship between current, resistance, and power in electrical circuits.