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In a closed loop circuit, if the sum of the voltage rises is 10V and the sum of

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Question: In a closed loop circuit, if the sum of the voltage rises is 10V and the sum of the voltage drops is 6V, what is the net voltage in the loop according to Kirchhoff\'s Voltage Law?

Options:

  1. 4V
  2. 6V
  3. 10V
  4. 16V

Correct Answer: 4V

Solution: 

According to Kirchhoff\'s Voltage Law, the net voltage in the loop is the sum of rises minus the sum of drops: 10V - 6V = 4V.

In a closed loop circuit, if the sum of the voltage rises is 10V and the sum of

Practice Questions

Q1
In a closed loop circuit, if the sum of the voltage rises is 10V and the sum of the voltage drops is 6V, what is the net voltage in the loop according to Kirchhoff's Voltage Law?
  1. 4V
  2. 6V
  3. 10V
  4. 16V

Questions & Step-by-Step Solutions

In a closed loop circuit, if the sum of the voltage rises is 10V and the sum of the voltage drops is 6V, what is the net voltage in the loop according to Kirchhoff's Voltage Law?
Correct Answer: 4V
  • Step 1: Identify the total voltage rises in the circuit. In this case, it is 10V.
  • Step 2: Identify the total voltage drops in the circuit. Here, it is 6V.
  • Step 3: Apply Kirchhoff's Voltage Law, which states that the net voltage in a closed loop is the sum of voltage rises minus the sum of voltage drops.
  • Step 4: Calculate the net voltage by subtracting the total voltage drops from the total voltage rises: 10V - 6V.
  • Step 5: Write down the result of the calculation, which is 4V.
  • Kirchhoff's Voltage Law – This law states that the sum of the electrical potential differences (voltage) around any closed network is zero, meaning that the total voltage rises must equal the total voltage drops.
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