What is the equivalent resistance of three resistors of 2Ω, 3Ω, and 6Ω connected

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Question: What is the equivalent resistance of three resistors of 2Ω, 3Ω, and 6Ω connected in parallel?

Options:

Correct Answer: 1Ω

Solution:

1/R_eq = 1/R1 + 1/R2 + 1/R3 = 1/2 + 1/3 + 1/6 = 1. Therefore, R_eq = 1Ω.

What is the equivalent resistance of three resistors of 2Ω, 3Ω, and 6Ω connected in parallel?

What is the equivalent resistance of three resistors of 2Ω, 3Ω, and 6Ω connected in parallel?

Correct Answer: 1Ω

Step 1: Identify the resistors and their values. We have three resistors: R1 = 2Ω, R2 = 3Ω, and R3 = 6Ω.
Step 2: Write the formula for equivalent resistance (R_eq) for resistors in parallel: 1/R_eq = 1/R1 + 1/R2 + 1/R3.
Step 3: Substitute the values of the resistors into the formula: 1/R_eq = 1/2 + 1/3 + 1/6.
Step 4: Calculate each term: 1/2 = 0.5, 1/3 ≈ 0.333, and 1/6 ≈ 0.167.
Step 5: Add the values together: 0.5 + 0.333 + 0.167 = 1.
Step 6: Since 1/R_eq = 1, we can find R_eq by taking the reciprocal: R_eq = 1Ω.

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