Question: In a circuit with two resistors in series, if the total voltage across the circuit is 12V and the resistors have values of 4Ω and 6Ω, what is the voltage across the 4Ω resistor?
Options:
Correct Answer: 6V
Solution:
Using the voltage divider rule, V1 = (R1 / (R1 + R2)) * Vtotal = (4 / (4 + 6)) * 12 = 4.8V.