A 3 kg object is thrown upwards with a velocity of 15 m/s. What is its maximum h

A 3 kg object is thrown upwards with a velocity of 15 m/s. What is its maximum height? (2020)

A 3 kg object is thrown upwards with a velocity of 15 m/s. What is its maximum height? (2020)

Step 1: Identify the initial velocity (u) of the object, which is given as 15 m/s.
Step 2: Identify the acceleration due to gravity (g), which is approximately 9.8 m/s².
Step 3: Use the formula for maximum height: h = u^2 / (2g).
Step 4: Calculate u^2, which is (15 m/s)² = 225 m²/s².
Step 5: Calculate 2g, which is 2 * 9.8 m/s² = 19.6 m/s².
Step 6: Divide u^2 by 2g to find h: h = 225 m²/s² / 19.6 m/s².
Step 7: Perform the division: h ≈ 11.48 m, which we can round to 11.5 m.

Kinematics – The study of motion, particularly the equations that describe the relationship between velocity, acceleration, and displacement.
Energy Conservation – Understanding how kinetic energy is converted to potential energy at the maximum height of the object's trajectory.
Gravitational Acceleration – The constant acceleration due to gravity (approximately 9.8 m/s²) that affects the object's motion.