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In a circuit with a 24V battery and two resistors of 8Ω and 4Ω in series, what i

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Question: In a circuit with a 24V battery and two resistors of 8Ω and 4Ω in series, what is the current flowing through the circuit?

Options:

  1. 2A
  2. 3A
  3. 4A
  4. 6A

Correct Answer: 3A

Solution: 

Total resistance R_total = 8Ω + 4Ω = 12Ω. Current I = V/R_total = 24V / 12Ω = 2A.

In a circuit with a 24V battery and two resistors of 8Ω and 4Ω in series, what i

Practice Questions

Q1
In a circuit with a 24V battery and two resistors of 8Ω and 4Ω in series, what is the current flowing through the circuit?
  1. 2A
  2. 3A
  3. 4A
  4. 6A

Questions & Step-by-Step Solutions

In a circuit with a 24V battery and two resistors of 8Ω and 4Ω in series, what is the current flowing through the circuit?
Correct Answer: 2A
  • Step 1: Identify the voltage of the battery, which is 24V.
  • Step 2: Identify the resistors in the circuit, which are 8Ω and 4Ω.
  • Step 3: Calculate the total resistance by adding the two resistors together: 8Ω + 4Ω = 12Ω.
  • Step 4: Use Ohm's Law to find the current. Ohm's Law states that Current (I) = Voltage (V) / Resistance (R).
  • Step 5: Substitute the values into the formula: I = 24V / 12Ω.
  • Step 6: Calculate the current: 24V divided by 12Ω equals 2A.
  • Ohm's Law – The relationship between voltage (V), current (I), and resistance (R) in an electrical circuit, expressed as V = I * R.
  • Series Circuits – In a series circuit, the total resistance is the sum of individual resistances, and the same current flows through all components.
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