What is the energy stored in a capacitor of capacitance 5μF charged to a potenti

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Question: What is the energy stored in a capacitor of capacitance 5μF charged to a potential difference of 10V? (2023)

Options:

Correct Answer: 0.5mJ

Exam Year: 2023

Solution:

Using the formula U = 1/2 CV², we have U = 1/2 * 5μF * (10V)² = 0.5mJ.

What is the energy stored in a capacitor of capacitance 5μF charged to a potential difference of 10V? (2023)

What is the energy stored in a capacitor of capacitance 5μF charged to a potential difference of 10V? (2023)

Step 1: Identify the formula for the energy stored in a capacitor, which is U = 1/2 CV².
Step 2: Identify the values needed for the formula: capacitance (C) is 5μF and potential difference (V) is 10V.
Step 3: Convert the capacitance from microfarads to farads: 5μF = 5 x 10^-6 F.
Step 4: Substitute the values into the formula: U = 1/2 * (5 x 10^-6 F) * (10V)².
Step 5: Calculate (10V)², which is 100V².
Step 6: Multiply 5 x 10^-6 F by 100V² to get 5 x 10^-4 J.
Step 7: Multiply by 1/2: U = 1/2 * 5 x 10^-4 J = 2.5 x 10^-4 J.
Step 8: Convert joules to millijoules: 2.5 x 10^-4 J = 0.25 mJ.

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