In a capacitor, if the charge is doubled while the voltage remains constant, wha

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Question: In a capacitor, if the charge is doubled while the voltage remains constant, what happens to the capacitance? (2019)

Options:

Correct Answer: It doubles

Exam Year: 2019

Solution:

Capacitance (C) is defined as C = Q/V. If the charge (Q) is doubled while the voltage (V) remains constant, the capacitance also doubles.

In a capacitor, if the charge is doubled while the voltage remains constant, what happens to the capacitance? (2019)

In a capacitor, if the charge is doubled while the voltage remains constant, what happens to the capacitance? (2019)

Step 1: Understand the formula for capacitance, which is C = Q/V, where C is capacitance, Q is charge, and V is voltage.
Step 2: Identify that in this scenario, the voltage (V) remains constant.
Step 3: Note that the charge (Q) is doubled, meaning if the original charge was Q, the new charge is 2Q.
Step 4: Substitute the new charge into the capacitance formula: C = (2Q)/V.
Step 5: Compare the new capacitance (C = (2Q)/V) with the original capacitance (C = Q/V).
Step 6: Since the new capacitance is twice the original capacitance, we conclude that the capacitance doubles.

Capacitance Definition – Capacitance (C) is defined as the ratio of charge (Q) stored to the voltage (V) across the capacitor, expressed as C = Q/V.
Relationship Between Charge, Voltage, and Capacitance – Understanding how changes in charge and voltage affect capacitance is crucial for solving problems related to capacitors.