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In a uniform electric field, the potential difference between two points is 10 V

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Question: In a uniform electric field, the potential difference between two points is 10 V. If the distance between these points is 2 m, what is the strength of the electric field? (2023)

Options:

  1. 5 N/C
  2. 10 N/C
  3. 20 N/C
  4. 2 N/C

Correct Answer: 5 N/C

Exam Year: 2023

Solution: 

E = V/d = 10 V / 2 m = 5 N/C.

In a uniform electric field, the potential difference between two points is 10 V

Practice Questions

Q1
In a uniform electric field, the potential difference between two points is 10 V. If the distance between these points is 2 m, what is the strength of the electric field? (2023)
  1. 5 N/C
  2. 10 N/C
  3. 20 N/C
  4. 2 N/C

Questions & Step-by-Step Solutions

In a uniform electric field, the potential difference between two points is 10 V. If the distance between these points is 2 m, what is the strength of the electric field? (2023)
  • Step 1: Understand that the electric field strength (E) can be calculated using the formula E = V/d, where V is the potential difference and d is the distance between the two points.
  • Step 2: Identify the values given in the question. The potential difference (V) is 10 volts and the distance (d) is 2 meters.
  • Step 3: Substitute the values into the formula: E = 10 V / 2 m.
  • Step 4: Perform the division: 10 V divided by 2 m equals 5 N/C.
  • Step 5: Conclude that the strength of the electric field is 5 N/C.
  • Electric Field Strength – The electric field strength (E) is defined as the potential difference (V) per unit distance (d) between two points in a uniform electric field.
  • Potential Difference – The potential difference is the work done per unit charge in moving a charge between two points in an electric field.
  • Uniform Electric Field – A uniform electric field is one where the electric field strength is constant in both magnitude and direction throughout the region.
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