If the current through a conductor is doubled while the resistance remains const

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Question: If the current through a conductor is doubled while the resistance remains constant, what happens to the power consumed?

Options:

Correct Answer: It doubles

Solution:

Power P = I^2 * R. If I is doubled, P becomes (2I)^2 * R = 4I^2 * R, which is four times the original power.

If the current through a conductor is doubled while the resistance remains constant, what happens to the power consumed?

If the current through a conductor is doubled while the resistance remains constant, what happens to the power consumed?

Correct Answer: Power becomes four times the original power.

Step 1: Understand the formula for power, which is P = I^2 * R, where P is power, I is current, and R is resistance.
Step 2: Identify that the current (I) is being doubled. If the original current is I, the new current will be 2I.
Step 3: Substitute the new current into the power formula. The new power will be P = (2I)^2 * R.
Step 4: Calculate (2I)^2, which equals 4I^2.
Step 5: Substitute this back into the power formula: P = 4I^2 * R.
Step 6: Compare the new power (4I^2 * R) to the original power (I^2 * R). The new power is four times the original power.

Ohm's Law and Power Calculation – Understanding the relationship between current, resistance, and power in electrical circuits.