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If the current through a conductor is doubled while the resistance remains const
If the current through a conductor is doubled while the resistance remains constant, what happens to the power consumed?
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Practice Questions
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Q1
If the current through a conductor is doubled while the resistance remains constant, what happens to the power consumed?
It doubles
It triples
It remains the same
It halves
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Power P = I^2 * R. If I is doubled, P becomes (2I)^2 * R = 4I^2 * R, which is four times the original power.
Questions & Step-by-step Solutions
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Q
Q: If the current through a conductor is doubled while the resistance remains constant, what happens to the power consumed?
Solution:
Power P = I^2 * R. If I is doubled, P becomes (2I)^2 * R = 4I^2 * R, which is four times the original power.
Steps: 6
Show Steps
Step 1: Understand the formula for power, which is P = I^2 * R, where P is power, I is current, and R is resistance.
Step 2: Identify that the current (I) is being doubled. If the original current is I, the new current will be 2I.
Step 3: Substitute the new current into the power formula. The new power will be P = (2I)^2 * R.
Step 4: Calculate (2I)^2, which equals 4I^2.
Step 5: Substitute this back into the power formula: P = 4I^2 * R.
Step 6: Compare the new power (4I^2 * R) to the original power (I^2 * R). The new power is four times the original power.
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