What is the osmotic pressure of a 0.5 M NaCl solution at 25°C? (R = 0.0821 L·atm
Practice Questions
Q1
What is the osmotic pressure of a 0.5 M NaCl solution at 25°C? (R = 0.0821 L·atm/(K·mol)) (2023)
12.3 atm
6.15 atm
3.07 atm
1.54 atm
Questions & Step-by-Step Solutions
What is the osmotic pressure of a 0.5 M NaCl solution at 25°C? (R = 0.0821 L·atm/(K·mol)) (2023)
Step 1: Identify the formula for osmotic pressure, which is π = iCRT.
Step 2: Determine the values needed for the formula: i (van 't Hoff factor), C (concentration in molarity), R (ideal gas constant), and T (temperature in Kelvin).
Step 3: For NaCl, the van 't Hoff factor (i) is 2 because NaCl dissociates into two ions: Na+ and Cl-.
Step 4: The concentration (C) is given as 0.5 M.
Step 5: The ideal gas constant (R) is given as 0.0821 L·atm/(K·mol).
Step 6: Convert the temperature from Celsius to Kelvin: 25°C + 273 = 298 K.
Step 7: Plug the values into the osmotic pressure formula: π = iCRT = 2 * 0.5 * 0.0821 * 298.
