In a simple cubic lattice, how many atoms are effectively present in one unit ce

Practice Questions

Q1
In a simple cubic lattice, how many atoms are effectively present in one unit cell? (2019)
  1. 1
  2. 2
  3. 4
  4. 8

Questions & Step-by-Step Solutions

In a simple cubic lattice, how many atoms are effectively present in one unit cell? (2019)
  • Step 1: Understand what a simple cubic lattice is. It is a 3D arrangement of atoms where each atom is located at the corners of a cube.
  • Step 2: Identify how many corners are in a cube. A cube has 8 corners.
  • Step 3: Know that each corner atom is shared by 8 adjacent unit cells. This means that only a fraction of each corner atom belongs to one unit cell.
  • Step 4: Calculate the contribution of each corner atom to the unit cell. Since each corner atom contributes 1/8th of an atom, you multiply the number of corners (8) by the contribution of each corner (1/8).
  • Step 5: Perform the calculation: 8 corners * (1/8) = 1 atom.
  • Step 6: Conclude that there is 1 atom effectively present in one unit cell of a simple cubic lattice.
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