In the reaction 2MnO4^- + 5C2O4^2- + 6H+ → 2Mn^2+ + 10CO2 + 3H2O, what is the ro

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Question: In the reaction 2MnO4^- + 5C2O4^2- + 6H+ → 2Mn^2+ + 10CO2 + 3H2O, what is the role of MnO4^-? (2023)

Options:

Correct Answer: Oxidizing agent

Exam Year: 2023

Solution:

MnO4^- acts as an oxidizing agent as it gains electrons and is reduced to Mn^2+.

In the reaction 2MnO4^- + 5C2O4^2- + 6H+ → 2Mn^2+ + 10CO2 + 3H2O, what is the role of MnO4^-? (2023)

In the reaction 2MnO4^- + 5C2O4^2- + 6H+ → 2Mn^2+ + 10CO2 + 3H2O, what is the role of MnO4^-? (2023)

Step 1: Identify the reactants in the reaction. The reactants are 2MnO4^-, 5C2O4^2-, and 6H+.
Step 2: Understand what happens to MnO4^- in the reaction. It changes to Mn^2+.
Step 3: Recognize that MnO4^- is gaining electrons during this process.
Step 4: Define what an oxidizing agent is. An oxidizing agent is a substance that gains electrons and gets reduced.
Step 5: Conclude that since MnO4^- gains electrons and is reduced to Mn^2+, it acts as an oxidizing agent.

Oxidation-Reduction Reactions – The reaction involves the transfer of electrons, where MnO4^- is reduced and C2O4^2- is oxidized.
Oxidizing Agent – An oxidizing agent is a substance that gains electrons in a chemical reaction, causing another substance to be oxidized.