A 4 kg object is lifted to a height of 5 m. What is the work done against gravit
Practice Questions
Q1
A 4 kg object is lifted to a height of 5 m. What is the work done against gravity? (g = 9.8 m/s²)
19.6 J
39.2 J
49 J
196 J
Questions & Step-by-Step Solutions
A 4 kg object is lifted to a height of 5 m. What is the work done against gravity? (g = 9.8 m/s²)
Step 1: Identify the mass of the object. In this case, the mass (m) is 4 kg.
Step 2: Identify the height to which the object is lifted. Here, the height (h) is 5 m.
Step 3: Identify the acceleration due to gravity. It is given as g = 9.8 m/s².
Step 4: Use the formula for work done against gravity, which is Work = mgh.
Step 5: Substitute the values into the formula: Work = 4 kg × 9.8 m/s² × 5 m.
Step 6: Calculate the result: 4 × 9.8 = 39.2, then 39.2 × 5 = 196.
Step 7: Conclude that the work done against gravity is 196 Joules (J).
Work Done Against Gravity – The work done against gravity is calculated using the formula W = mgh, where W is work, m is mass, g is acceleration due to gravity, and h is height.
