What is the work done when a force of 15 N moves an object 3 m at an angle of 60

₹0.0

Question: What is the work done when a force of 15 N moves an object 3 m at an angle of 60° to the direction of the force?

Options:

Correct Answer: 22.5 J

Solution:

W = F × d × cos(θ) = 15 N × 3 m × cos(60°) = 15 × 3 × 0.5 = 22.5 J.

What is the work done when a force of 15 N moves an object 3 m at an angle of 60° to the direction of the force?

What is the work done when a force of 15 N moves an object 3 m at an angle of 60° to the direction of the force?

Step 1: Identify the force applied, which is 15 N.
Step 2: Identify the distance the object is moved, which is 3 m.
Step 3: Identify the angle between the force and the direction of movement, which is 60°.
Step 4: Use the formula for work done: W = F × d × cos(θ).
Step 5: Substitute the values into the formula: W = 15 N × 3 m × cos(60°).
Step 6: Calculate cos(60°), which is 0.5.
Step 7: Substitute cos(60°) into the equation: W = 15 N × 3 m × 0.5.
Step 8: Calculate the work done: W = 15 × 3 × 0.5 = 22.5 J.

No concepts available.