What is the equivalent resistance of three resistors, 2Ω, 3Ω, and 6Ω, connected in series?
Practice Questions
1 question
Q1
What is the equivalent resistance of three resistors, 2Ω, 3Ω, and 6Ω, connected in series?
11Ω
6Ω
3Ω
2Ω
In series, the equivalent resistance is the sum of the individual resistances: R_eq = R1 + R2 + R3 = 2Ω + 3Ω + 6Ω = 11Ω.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the equivalent resistance of three resistors, 2Ω, 3Ω, and 6Ω, connected in series?
Solution: In series, the equivalent resistance is the sum of the individual resistances: R_eq = R1 + R2 + R3 = 2Ω + 3Ω + 6Ω = 11Ω.
Steps: 6
Step 1: Identify the resistors and their values. We have three resistors: R1 = 2Ω, R2 = 3Ω, and R3 = 6Ω.
Step 2: Understand that when resistors are connected in series, the total or equivalent resistance (R_eq) is found by adding their individual resistances together.
Step 3: Write the formula for equivalent resistance in series: R_eq = R1 + R2 + R3.
Step 4: Substitute the values of the resistors into the formula: R_eq = 2Ω + 3Ω + 6Ω.
Step 5: Perform the addition: 2 + 3 = 5, then 5 + 6 = 11.
Step 6: Conclude that the equivalent resistance of the three resistors in series is 11Ω.
