What is the equivalent resistance of three resistors, 2Ω, 3Ω, and 6Ω, connected

₹0.0

Question: What is the equivalent resistance of three resistors, 2Ω, 3Ω, and 6Ω, connected in series?

Options:

Correct Answer: 11Ω

Solution:

In series, the equivalent resistance is the sum of the individual resistances: R_eq = R1 + R2 + R3 = 2Ω + 3Ω + 6Ω = 11Ω.

What is the equivalent resistance of three resistors, 2Ω, 3Ω, and 6Ω, connected in series?

What is the equivalent resistance of three resistors, 2Ω, 3Ω, and 6Ω, connected in series?

Correct Answer: 11Ω

Step 1: Identify the resistors and their values. We have three resistors: R1 = 2Ω, R2 = 3Ω, and R3 = 6Ω.
Step 2: Understand that when resistors are connected in series, the total or equivalent resistance (R_eq) is found by adding their individual resistances together.
Step 3: Write the formula for equivalent resistance in series: R_eq = R1 + R2 + R3.
Step 4: Substitute the values of the resistors into the formula: R_eq = 2Ω + 3Ω + 6Ω.
Step 5: Perform the addition: 2 + 3 = 5, then 5 + 6 = 11.
Step 6: Conclude that the equivalent resistance of the three resistors in series is 11Ω.

No concepts available.