What is the total resistance in a circuit with a 4Ω and a 6Ω resistor in series?

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Question: What is the total resistance in a circuit with a 4Ω and a 6Ω resistor in series? (2022)

Options:

Correct Answer: 10Ω

Exam Year: 2022

Solution:

In series, R_total = R1 + R2 = 4Ω + 6Ω = 10Ω.

What is the total resistance in a circuit with a 4Ω and a 6Ω resistor in series? (2022)

What is the total resistance in a circuit with a 4Ω and a 6Ω resistor in series? (2022)

Step 1: Identify the resistors in the circuit. We have a 4Ω resistor and a 6Ω resistor.
Step 2: Understand that in a series circuit, the total resistance is found by adding the resistances together.
Step 3: Write down the formula for total resistance in series: R_total = R1 + R2.
Step 4: Substitute the values of the resistors into the formula: R_total = 4Ω + 6Ω.
Step 5: Perform the addition: 4Ω + 6Ω = 10Ω.
Step 6: Conclude that the total resistance in the circuit is 10Ω.

No concepts available.