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What is the output of the following C++ code for a binary tree with root value 1

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Question: What is the output of the following C++ code for a binary tree with root value 1, left child 2, and right child 3 during pre-order traversal?

Options:

  1. 1 2 3
  2. 2 1 3
  3. 1 3 2
  4. 3 2 1

Correct Answer: 1 2 3

Solution: 

Pre-order traversal visits the root first, then the left subtree, followed by the right subtree, resulting in the output \'1 2 3\'.

What is the output of the following C++ code for a binary tree with root value 1

Practice Questions

Q1
What is the output of the following C++ code for a binary tree with root value 1, left child 2, and right child 3 during pre-order traversal?
  1. 1 2 3
  2. 2 1 3
  3. 1 3 2
  4. 3 2 1

Questions & Step-by-Step Solutions

What is the output of the following C++ code for a binary tree with root value 1, left child 2, and right child 3 during pre-order traversal?
  • Step 1: Understand what a binary tree is. A binary tree is a structure where each node has at most two children, referred to as the left child and the right child.
  • Step 2: Identify the structure of the binary tree given in the question. The root node has a value of 1, the left child has a value of 2, and the right child has a value of 3.
  • Step 3: Learn about pre-order traversal. In pre-order traversal, we visit the nodes in the following order: first the root node, then the left subtree, and finally the right subtree.
  • Step 4: Apply pre-order traversal to the binary tree. Start with the root node (1), then move to the left child (2), and finally to the right child (3).
  • Step 5: Write down the order of the values visited during pre-order traversal. The order is 1 (root), then 2 (left child), and finally 3 (right child).
  • Step 6: Combine the values into a single output string. The final output is '1 2 3'.
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