In a circuit with a 9V battery and two resistors of 3 ohms and 6 ohms in paralle

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Question: In a circuit with a 9V battery and two resistors of 3 ohms and 6 ohms in parallel, what is the equivalent resistance?

Options:

Correct Answer: 2 ohms

Solution:

1/R_eq = 1/R1 + 1/R2 = 1/3 + 1/6 = 1/2, R_eq = 2 ohms.

In a circuit with a 9V battery and two resistors of 3 ohms and 6 ohms in parallel, what is the equivalent resistance?

In a circuit with a 9V battery and two resistors of 3 ohms and 6 ohms in parallel, what is the equivalent resistance?

Correct Answer: 2 ohms

Step 1: Identify the resistors in the circuit. We have R1 = 3 ohms and R2 = 6 ohms.
Step 2: Use the formula for equivalent resistance in parallel circuits: 1/R_eq = 1/R1 + 1/R2.
Step 3: Substitute the values of R1 and R2 into the formula: 1/R_eq = 1/3 + 1/6.
Step 4: Find a common denominator to add the fractions. The common denominator for 3 and 6 is 6.
Step 5: Rewrite 1/3 as 2/6, so now we have: 1/R_eq = 2/6 + 1/6.
Step 6: Add the fractions: 1/R_eq = (2 + 1)/6 = 3/6.
Step 7: Simplify 3/6 to 1/2, so we have: 1/R_eq = 1/2.
Step 8: To find R_eq, take the reciprocal of 1/2: R_eq = 2 ohms.

Equivalent Resistance in Parallel Circuits – This concept involves calculating the total resistance of resistors connected in parallel using the formula 1/R_eq = 1/R1 + 1/R2.