A charge of +5 μC is placed in an electric field of 1000 N/C. What is the work d

A charge of +5 μC is placed in an electric field of 1000 N/C. What is the work done in moving the charge 0.2 m in the direction of the field? (2022)

A charge of +5 μC is placed in an electric field of 1000 N/C. What is the work done in moving the charge 0.2 m in the direction of the field? (2022)

Step 1: Identify the given values. We have a charge (q) of +5 μC (which is 5 × 10^-6 C) and an electric field (E) of 1000 N/C.
Step 2: Convert the charge from microcoulombs to coulombs. +5 μC = 5 × 10^-6 C.
Step 3: Identify the distance (d) the charge is moved, which is 0.2 m.
Step 4: Use the formula for work done (W) in an electric field: W = F * d, where F is the force on the charge.
Step 5: Calculate the force (F) using the formula F = E * q. Substitute the values: F = 1000 N/C * 5 × 10^-6 C.
Step 6: Calculate the force: F = 1000 * 5 × 10^-6 = 0.005 N.
Step 7: Now, substitute the force (F) and distance (d) into the work formula: W = F * d = 0.005 N * 0.2 m.
Step 8: Calculate the work done: W = 0.005 * 0.2 = 0.001 J.
Step 9: Correctly calculate the work done using the correct formula: W = (E * q) * d = (1000 N/C * 5 × 10^-6 C) * 0.2 m.
Step 10: Final calculation: W = (1000 * 5 × 10^-6) * 0.2 = 0.1 J.

Electric Work Calculation – The work done on a charge in an electric field is calculated using the formula W = F * d, where F is the force acting on the charge, derived from the electric field (E) and the charge (q).
Understanding Electric Fields – An electric field (E) is defined as the force per unit charge, and it is crucial to understand how it interacts with charges placed within it.