Question: A 2 kg block is sliding down a frictionless incline of height 5 m. What is its speed at the bottom?
Options:
Correct Answer: 10 m/s
Solution:
Using conservation of energy, potential energy at the top = kinetic energy at the bottom: mgh = 0.5mv². Solving gives v = √(2gh) = √(2 * 9.8 * 5) = 10 m/s.