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What is the voltage drop across a 5 ohm resistor carrying a current of 2 A?

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Question: What is the voltage drop across a 5 ohm resistor carrying a current of 2 A?

Options:

  1. 5 V
  2. 10 V
  3. 15 V
  4. 20 V

Correct Answer: 10 V

Solution: 

Using Ohm\'s law, V = I * R = 2 A * 5 ohms = 10 V.

What is the voltage drop across a 5 ohm resistor carrying a current of 2 A?

Practice Questions

Q1
What is the voltage drop across a 5 ohm resistor carrying a current of 2 A?
  1. 5 V
  2. 10 V
  3. 15 V
  4. 20 V

Questions & Step-by-Step Solutions

What is the voltage drop across a 5 ohm resistor carrying a current of 2 A?
Correct Answer: 10 V
  • Step 1: Identify the values given in the problem. We have a resistor with a resistance of 5 ohms and a current of 2 A.
  • Step 2: Recall Ohm's law, which states that voltage (V) is equal to current (I) multiplied by resistance (R). The formula is V = I * R.
  • Step 3: Substitute the values into the formula. Here, I = 2 A and R = 5 ohms.
  • Step 4: Calculate the voltage drop. Multiply 2 A by 5 ohms: 2 * 5 = 10.
  • Step 5: Conclude that the voltage drop across the 5 ohm resistor is 10 V.
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