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What is the equivalent resistance of two resistors of 8Ω and 12Ω connected in se

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Question: What is the equivalent resistance of two resistors of 8Ω and 12Ω connected in series? (2019)

Options:

  1. 20Ω
  2. 24Ω
  3. 16Ω
  4. 10Ω

Correct Answer: 20Ω

Exam Year: 2019

Solution: 

In series, R_eq = R1 + R2 = 8Ω + 12Ω = 20Ω.

What is the equivalent resistance of two resistors of 8Ω and 12Ω connected in se

Practice Questions

Q1
What is the equivalent resistance of two resistors of 8Ω and 12Ω connected in series? (2019)
  1. 20Ω
  2. 24Ω
  3. 16Ω
  4. 10Ω

Questions & Step-by-Step Solutions

What is the equivalent resistance of two resistors of 8Ω and 12Ω connected in series? (2019)
  • Step 1: Identify the resistors. We have two resistors: one is 8Ω and the other is 12Ω.
  • Step 2: Understand that when resistors are connected in series, you add their resistances together.
  • Step 3: Write the formula for equivalent resistance in series: R_eq = R1 + R2.
  • Step 4: Substitute the values of the resistors into the formula: R_eq = 8Ω + 12Ω.
  • Step 5: Perform the addition: 8 + 12 = 20.
  • Step 6: Conclude that the equivalent resistance is 20Ω.
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