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In the electrochemical series, which element is the strongest oxidizing agent? (

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Question: In the electrochemical series, which element is the strongest oxidizing agent? (2023)

Options:

  1. Li
  2. F2
  3. Na
  4. K

Correct Answer: F2

Exam Year: 2023

Solution:

Fluorine (F2) is the strongest oxidizing agent in the electrochemical series due to its high electronegativity and tendency to gain electrons.

In the electrochemical series, which element is the strongest oxidizing agent? (

Practice Questions

Q1
In the electrochemical series, which element is the strongest oxidizing agent? (2023)
  1. Li
  2. F2
  3. Na
  4. K

Questions & Step-by-Step Solutions

In the electrochemical series, which element is the strongest oxidizing agent? (2023)
  • Step 1: Understand what an oxidizing agent is. An oxidizing agent is a substance that can gain electrons and cause another substance to be oxidized.
  • Step 2: Learn about the electrochemical series. This is a list of elements arranged by their ability to gain electrons.
  • Step 3: Identify the element with the highest tendency to gain electrons in the electrochemical series.
  • Step 4: Recognize that fluorine (F2) is at the top of the electrochemical series.
  • Step 5: Understand that fluorine has high electronegativity, meaning it strongly attracts electrons.
  • Step 6: Conclude that because of its position in the series and its properties, fluorine is the strongest oxidizing agent.
  • Electrochemical Series – A ranking of elements based on their standard electrode potentials, indicating their ability to act as oxidizing or reducing agents.
  • Oxidizing Agents – Substances that can accept electrons in a chemical reaction, thereby causing another substance to be oxidized.
  • Electronegativity – A measure of the tendency of an atom to attract a bonding pair of electrons, influencing its ability to act as an oxidizing agent.
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