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What is the work done by an ideal gas during an isobaric expansion if the pressu

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Question: What is the work done by an ideal gas during an isobaric expansion if the pressure is 5 atm and the volume changes from 2 L to 5 L? (2019)

Options:

  1. 15 L·atm
  2. 10 L·atm
  3. 5 L·atm
  4. 20 L·atm

Correct Answer: 15 L·atm

Exam Year: 2019

Solution: 

Work done (W) = PΔV = P(V_final - V_initial) = 5 atm * (5 L - 2 L) = 15 L·atm.

What is the work done by an ideal gas during an isobaric expansion if the pressu

Practice Questions

Q1
What is the work done by an ideal gas during an isobaric expansion if the pressure is 5 atm and the volume changes from 2 L to 5 L? (2019)
  1. 15 L·atm
  2. 10 L·atm
  3. 5 L·atm
  4. 20 L·atm

Questions & Step-by-Step Solutions

What is the work done by an ideal gas during an isobaric expansion if the pressure is 5 atm and the volume changes from 2 L to 5 L? (2019)
  • Step 1: Identify the pressure (P) of the gas, which is given as 5 atm.
  • Step 2: Identify the initial volume (V_initial), which is given as 2 L.
  • Step 3: Identify the final volume (V_final), which is given as 5 L.
  • Step 4: Calculate the change in volume (ΔV) by subtracting the initial volume from the final volume: ΔV = V_final - V_initial = 5 L - 2 L.
  • Step 5: Calculate ΔV, which equals 3 L.
  • Step 6: Use the formula for work done (W) during isobaric expansion: W = P * ΔV.
  • Step 7: Substitute the values into the formula: W = 5 atm * 3 L.
  • Step 8: Calculate the work done: W = 15 L·atm.
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