A capacitor of 10μF is connected to an AC source of frequency 50Hz. What is the

A capacitor of 10μF is connected to an AC source of frequency 50Hz. What is the capacitive reactance? (2022)

A capacitor of 10μF is connected to an AC source of frequency 50Hz. What is the capacitive reactance? (2022)

Step 1: Identify the values given in the problem. We have a capacitor value C = 10μF (microfarads) and a frequency f = 50Hz.
Step 2: Convert the capacitor value from microfarads to farads. 10μF = 10 * 10^-6 F = 10e-6 F.
Step 3: Write down the formula for capacitive reactance (XC). The formula is XC = 1 / (2πfC).
Step 4: Substitute the values into the formula. XC = 1 / (2π * 50 * 10e-6).
Step 5: Calculate the denominator first: 2π * 50 * 10e-6.
Step 6: Use a calculator to find the value of the denominator, which is approximately 0.00031416.
Step 7: Now, calculate XC by taking the reciprocal of the denominator: XC ≈ 1 / 0.00031416.
Step 8: The result of the calculation gives XC ≈ 318.3Ω.

Capacitive Reactance – Capacitive reactance (XC) is the opposition that a capacitor offers to the flow of alternating current (AC), calculated using the formula XC = 1/(2πfC), where f is the frequency and C is the capacitance.
AC Circuit Analysis – Understanding how capacitors behave in AC circuits, including the relationship between frequency, capacitance, and reactance.