If a charge of +2μC is placed in an electric field of 500 N/C, what is the force

If a charge of +2μC is placed in an electric field of 500 N/C, what is the force experienced by the charge? (2022)

If a charge of +2μC is placed in an electric field of 500 N/C, what is the force experienced by the charge? (2022)

Step 1: Identify the charge (q) given in the problem, which is +2μC (microcoulombs).
Step 2: Convert the charge from microcoulombs to coulombs. 1μC = 1 x 10^-6 C, so +2μC = 2 x 10^-6 C.
Step 3: Identify the electric field strength (E) given in the problem, which is 500 N/C.
Step 4: Use the formula for force (F) on a charge in an electric field, which is F = qE.
Step 5: Substitute the values into the formula: F = (2 x 10^-6 C) * (500 N/C).
Step 6: Calculate the force: F = 1000 x 10^-6 N = 0.001 N or 1 N.

Electric Force Calculation – The question tests the understanding of how to calculate the force experienced by a charge in an electric field using the formula F = qE.