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What is the energy of a photon with a frequency of 6 x 10^14 Hz?

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Question: What is the energy of a photon with a frequency of 6 x 10^14 Hz?

Options:

  1. 3.31 x 10^-19 J
  2. 1.24 x 10^-19 J
  3. 4.14 x 10^-19 J
  4. 2.00 x 10^-19 J

Correct Answer: 4.14 x 10^-19 J

Solution: 

The energy of a photon is given by E = h * f, where h = 6.63 x 10^-34 J·s. Thus, E = 6.63 x 10^-34 * 6 x 10^14 = 4.14 x 10^-19 J.

What is the energy of a photon with a frequency of 6 x 10^14 Hz?

Practice Questions

Q1
What is the energy of a photon with a frequency of 6 x 10^14 Hz?
  1. 3.31 x 10^-19 J
  2. 1.24 x 10^-19 J
  3. 4.14 x 10^-19 J
  4. 2.00 x 10^-19 J

Questions & Step-by-Step Solutions

What is the energy of a photon with a frequency of 6 x 10^14 Hz?
Correct Answer: 4.14 x 10^-19 J
  • Step 1: Identify the formula for the energy of a photon, which is E = h * f.
  • Step 2: Note the value of Planck's constant (h), which is 6.63 x 10^-34 J·s.
  • Step 3: Identify the frequency (f) of the photon, which is given as 6 x 10^14 Hz.
  • Step 4: Substitute the values into the formula: E = (6.63 x 10^-34 J·s) * (6 x 10^14 Hz).
  • Step 5: Perform the multiplication: 6.63 * 6 = 39.78 and 10^-34 * 10^14 = 10^-20.
  • Step 6: Combine the results: E = 39.78 x 10^-20 J.
  • Step 7: Convert 39.78 x 10^-20 J to scientific notation: E = 4.14 x 10^-19 J.
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