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What is the critical angle for total internal reflection when light travels from
What is the critical angle for total internal reflection when light travels from water (n=1.33) to air (n=1.00)?
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Practice Questions
1 question
Q1
What is the critical angle for total internal reflection when light travels from water (n=1.33) to air (n=1.00)?
48.6 degrees
41.8 degrees
53.1 degrees
60.0 degrees
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The critical angle θc can be calculated using sin(θc) = n2/n1 = 1.00/1.33, which gives θc ≈ 48.6 degrees.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the critical angle for total internal reflection when light travels from water (n=1.33) to air (n=1.00)?
Solution:
The critical angle θc can be calculated using sin(θc) = n2/n1 = 1.00/1.33, which gives θc ≈ 48.6 degrees.
Steps: 7
Show Steps
Step 1: Understand that the critical angle is the angle of incidence above which total internal reflection occurs.
Step 2: Identify the refractive indices of the two materials: water (n1 = 1.33) and air (n2 = 1.00).
Step 3: Use the formula for the critical angle: sin(θc) = n2 / n1.
Step 4: Substitute the values into the formula: sin(θc) = 1.00 / 1.33.
Step 5: Calculate the value: sin(θc) ≈ 0.7519.
Step 6: Use the inverse sine function to find θc: θc = sin⁻¹(0.7519).
Step 7: Calculate θc, which is approximately 48.6 degrees.
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