In a binary search tree, what is the time complexity for inserting an element in
Practice Questions
Q1
In a binary search tree, what is the time complexity for inserting an element in the average case?
O(1)
O(log n)
O(n)
O(n log n)
Questions & Step-by-Step Solutions
In a binary search tree, what is the time complexity for inserting an element in the average case?
Step 1: Understand what a binary search tree (BST) is. A BST is a data structure where each node has at most two children, and the left child is less than the parent node, while the right child is greater.
Step 2: Know that when we insert an element into a BST, we start at the root and compare the new element with the current node's value.
Step 3: If the new element is smaller, we move to the left child; if it's larger, we move to the right child.
Step 4: We repeat this process until we find an empty spot where we can insert the new element.
Step 5: In a balanced BST, the height of the tree is log(n), where n is the number of nodes. This is because each comparison allows us to eliminate half of the remaining nodes.
Step 6: Therefore, in the average case, the time it takes to insert an element is proportional to the height of the tree, which is O(log n).
