A 3 kg object is dropped from a height of 5 m. What is the potential energy at t

A 3 kg object is dropped from a height of 5 m. What is the potential energy at the top? (g = 9.8 m/s²)

A 3 kg object is dropped from a height of 5 m. What is the potential energy at the top? (g = 9.8 m/s²)

Step 1: Identify the mass of the object. In this case, the mass (m) is 3 kg.
Step 2: Identify the height from which the object is dropped. The height (h) is 5 m.
Step 3: Identify the acceleration due to gravity. The value of g is 9.8 m/s².
Step 4: Use the formula for potential energy (PE), which is PE = mgh.
Step 5: Substitute the values into the formula: PE = 3 kg × 9.8 m/s² × 5 m.
Step 6: Calculate the result: 3 × 9.8 = 29.4, then 29.4 × 5 = 147.
Step 7: Conclude that the potential energy at the top is 147 Joules (J).

Potential Energy – Potential energy is the energy stored in an object due to its position in a gravitational field, calculated using the formula PE = mgh, where m is mass, g is acceleration due to gravity, and h is height.