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What is the work done when 1 mole of an ideal gas expands isothermally from 10 L to 20 L at a temperature of 300 K? (2020)

Practice Questions

1 question
Q1
What is the work done when 1 mole of an ideal gas expands isothermally from 10 L to 20 L at a temperature of 300 K? (2020)
  1. 1.5 kJ
  2. 2.5 kJ
  3. 3.5 kJ
  4. 4.5 kJ

Questions & Step-by-step Solutions

1 item
Q
Q: What is the work done when 1 mole of an ideal gas expands isothermally from 10 L to 20 L at a temperature of 300 K? (2020)
Solution: Work done (W) = nRT ln(Vf/Vi) = 1 mol * 8.314 J/(mol K) * 300 K * ln(20/10) = 2.5 kJ.
Steps: 0

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