What is the latent heat of fusion of ice if 80 g of ice at 0°C melts to water at 0°C, absorbing 3360 J of heat? (2022)
Practice Questions
1 question
Q1
What is the latent heat of fusion of ice if 80 g of ice at 0°C melts to water at 0°C, absorbing 3360 J of heat? (2022)
40 J/g
60 J/g
80 J/g
100 J/g
Latent heat of fusion (L) = Q/m = 3360 J / 80 g = 42 J/g.
Questions & Step-by-step Solutions
1 item
Q
Q: What is the latent heat of fusion of ice if 80 g of ice at 0°C melts to water at 0°C, absorbing 3360 J of heat? (2022)
Solution: Latent heat of fusion (L) = Q/m = 3360 J / 80 g = 42 J/g.
Steps: 6
Step 1: Understand the problem. We need to find the latent heat of fusion of ice, which is the amount of heat required to melt ice without changing its temperature.
Step 2: Identify the given values. We have 80 grams of ice (m = 80 g) and the heat absorbed (Q = 3360 J).
Step 3: Use the formula for latent heat of fusion: L = Q / m, where L is the latent heat of fusion, Q is the heat absorbed, and m is the mass of the ice.
Step 4: Substitute the values into the formula: L = 3360 J / 80 g.
Step 5: Calculate the result: L = 42 J/g.
Step 6: Conclude that the latent heat of fusion of ice is 42 J/g.
