A 5 kg object is lifted to a height of 2 m. How much work is done against gravit

A 5 kg object is lifted to a height of 2 m. How much work is done against gravity? (g = 9.8 m/s²) (2022)

A 5 kg object is lifted to a height of 2 m. How much work is done against gravity? (g = 9.8 m/s²) (2022)

Step 1: Identify the mass of the object. In this case, the mass (m) is 5 kg.
Step 2: Identify the height to which the object is lifted. Here, the height (h) is 2 m.
Step 3: Identify the acceleration due to gravity. It is given as g = 9.8 m/s².
Step 4: Use the formula for work done against gravity, which is Work = m * g * h.
Step 5: Substitute the values into the formula: Work = 5 kg * 9.8 m/s² * 2 m.
Step 6: Calculate the result: 5 * 9.8 * 2 = 98 J.
Step 7: Conclude that the work done against gravity is 98 Joules.

Work Done Against Gravity – The work done against gravity is calculated using the formula W = mgh, where W is work, m is mass, g is acceleration due to gravity, and h is height.