The maximum speed of a simple harmonic oscillator is 4 m/s. If the amplitude is

Practice Questions

Q1
The maximum speed of a simple harmonic oscillator is 4 m/s. If the amplitude is 2 m, what is the angular frequency? (2019)
  1. 2 rad/s
  2. 4 rad/s
  3. 1 rad/s
  4. 8 rad/s

Questions & Step-by-Step Solutions

The maximum speed of a simple harmonic oscillator is 4 m/s. If the amplitude is 2 m, what is the angular frequency? (2019)
  • Step 1: Understand the terms. The maximum speed (v_max) of the oscillator is given as 4 m/s, and the amplitude (A) is given as 2 m.
  • Step 2: Recall the formula that relates maximum speed, angular frequency (ω), and amplitude: v_max = ωA.
  • Step 3: Rearrange the formula to solve for angular frequency (ω): ω = v_max / A.
  • Step 4: Substitute the values into the formula: ω = 4 m/s / 2 m.
  • Step 5: Perform the division: ω = 2 rad/s.
No concepts available.
Soulshift Feedback ×

On a scale of 0–10, how likely are you to recommend The Soulshift Academy?

Not likely Very likely