Question: In the reaction 2MnO4⁻ + 5C2O4²⁻ + 16H⁺ → 2Mn²⁺ + 10CO2 + 8H2O, which species is reduced? (2019)
Options:
MnO4⁻
C2O4²⁻
H⁺
CO2
Correct Answer: MnO4⁻
Exam Year: 2019
Solution:
In this reaction, MnO4⁻ is reduced to Mn²⁺ as it gains electrons.
In the reaction 2MnO4⁻ + 5C2O4²⁻ + 16H⁺ → 2Mn²⁺ + 10CO2 + 8H2O, which species is
Practice Questions
Q1
In the reaction 2MnO4⁻ + 5C2O4²⁻ + 16H⁺ → 2Mn²⁺ + 10CO2 + 8H2O, which species is reduced? (2019)
MnO4⁻
C2O4²⁻
H⁺
CO2
Questions & Step-by-Step Solutions
In the reaction 2MnO4⁻ + 5C2O4²⁻ + 16H⁺ → 2Mn²⁺ + 10CO2 + 8H2O, which species is reduced? (2019)
Step 1: Identify the reactants and products in the reaction.
Step 2: Look for the oxidation states of the elements in the reactants and products.
Step 3: Determine the oxidation state of manganese (Mn) in MnO4⁻. It is +7.
Step 4: Determine the oxidation state of manganese (Mn) in Mn²⁺. It is +2.
Step 5: Compare the oxidation states. Mn goes from +7 to +2, which means it gains electrons.
Step 6: Since gaining electrons indicates reduction, MnO4⁻ is the species that is reduced.
Redox Reactions – Understanding oxidation and reduction processes, specifically identifying which species gains electrons (is reduced) and which loses electrons (is oxidized).
Oxidation States – Calculating and comparing oxidation states of elements in compounds to determine changes during the reaction.
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