For the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), what happens if the volume of the co

Practice Questions

Q1
For the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), what happens if the volume of the container is decreased? (2021)
  1. Equilibrium shifts to the left
  2. Equilibrium shifts to the right
  3. No change
  4. Depends on temperature

Questions & Step-by-Step Solutions

For the reaction 2SO2(g) + O2(g) ⇌ 2SO3(g), what happens if the volume of the container is decreased? (2021)
  • Step 1: Understand that the reaction involves gases: 2SO2, O2, and 2SO3.
  • Step 2: Recognize that decreasing the volume of the container increases the pressure of the gases inside.
  • Step 3: Recall Le Chatelier's principle, which states that if a system at equilibrium is disturbed, it will shift to counteract the disturbance.
  • Step 4: Identify the number of moles of gas on each side of the reaction: the left side has 3 moles (2SO2 + O2) and the right side has 2 moles (2SO3).
  • Step 5: Since the right side has fewer moles of gas, the equilibrium will shift to the right to reduce pressure.
  • Le Chatelier's Principle – This principle states that if a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium shifts to counteract the change.
  • Gas Laws – Understanding how changes in volume affect pressure and the behavior of gases in a chemical reaction.
  • Stoichiometry – The relationship between the quantities of reactants and products in a chemical reaction, particularly in terms of moles of gas.
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